document.write( "Question 903849: Larry MItchell invested part of his $17,000 advance at 6% annual simple interest and the rest at 9% annal simple interest. If his total yearly interest from both accounts was $1,230, find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #548356 by richwmiller(17219)\"\" \"About 
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We know the total amount of money invested. $17000
\n" ); document.write( "x+y=17000,
\n" ); document.write( "We know that the total interest for the year for the two accounts is $1230
\n" ); document.write( "0.06*x+0.09*y=1230
\n" ); document.write( "x=17000-y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.06*(17000-y)+0.09*y=1230
\n" ); document.write( "We multiply out
\n" ); document.write( "1020-0.06y+0.09*y=1230
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.03*y=210
\n" ); document.write( "Isolate y
\n" ); document.write( "y=7000 at 9%
\n" ); document.write( "x=17000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=10000 at 6%
\n" ); document.write( "We check
\n" ); document.write( "0.06*10000+0.09*7000=1230
\n" ); document.write( "600+630=1230
\n" ); document.write( "1230=1230
\n" ); document.write( "Since this statement is TRUE and neither amount is negative then it is ok
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