document.write( "Question 903825: Evaluate the following algebraic expressions for given value of the variables.
\n" ); document.write( "3-5x; x=-4 \r
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\n" ); document.write( "\n" ); document.write( "(3x-2)(y-1);x=2/3,y=1
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Algebra.Com's Answer #548321 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "3-5x\r
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\n" ); document.write( "\n" ); document.write( "3-5(-4) ... replace every x with -4\r
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\n" ); document.write( "\n" ); document.write( "3 + 20\r
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\n" ); document.write( "\n" ); document.write( "23\r
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\n" ); document.write( "\n" ); document.write( "So 3-5x = 23 when x = -4\r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "(3x-2)(y-1)\r
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\n" ); document.write( "\n" ); document.write( "(3(2/3)-2)(y-1) ... replace every x with 2/3\r
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\n" ); document.write( "\n" ); document.write( "(3(2/3)-2)(1-1) ... replace every y with 1\r
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\n" ); document.write( "\n" ); document.write( "(2-2)(1-1)\r
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\n" ); document.write( "\n" ); document.write( "0*0\r
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\n" ); document.write( "\n" ); document.write( "0\r
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\n" ); document.write( "\n" ); document.write( "That means (3x-2)(y-1) = 0 when x = 2/3 and y = 1
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