document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903800>Question 903800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alex and Brian are driving golf carts on the same path in the same direction. Alex's cart is traveling at 4 miles per hour and Brian's cart is traveling at 8 miles per hour. Alex passes a lemonade stand at 11:40 A.M. If Brian passes the same lemonade stand at 11:52 A.M., at what time will Brian catch up to Alex? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548304 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> gaining speed 8 -4= 4 mph<BR>\n" );
document.write( "headstart  4*0.2 =0.8 miles<BR>\n" );
document.write( "time to catch up 0.8/4=0.2 hours<BR>\n" );
document.write( "time to catch up =12 minutes<BR>\n" );
document.write( "alegebraic solution<BR>\n" );
document.write( "4(t+0.2)=8t<BR>\n" );
document.write( "4t+0.8=8t<BR>\n" );
document.write( "0.8=8t-4t<BR>\n" );
document.write( "0.8=4t<BR>\n" );
document.write( "0.2=t<BR>\n" );
document.write( "distance to meeting 0.2*8=1.6 miles<BR>\n" );
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