document.write( "Question 76444This question is from textbook College Algebra
\n" ); document.write( ": sq rt 3x+1 +2=4\r
\n" ); document.write( "\n" ); document.write( "i have not a clue on how to do this and its going to be on a test...this is on page 387
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Algebra.Com's Answer #54823 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
sq rt 3x+1 + 2 = 4
\n" ); document.write( ":
\n" ); document.write( "I assume you mean:
\n" ); document.write( "\"sqrt%283x%2B1%29\" + 2 = 4
\n" ); document.write( ":
\n" ); document.write( "If you can get the square root on one side of the equation by itself, it
\n" ); document.write( "becomes an easy matter to get rid of the radical by squaring both sides
\n" ); document.write( ":
\n" ); document.write( "Subtract 2 from both sides and you have:
\n" ); document.write( "\"sqrt%283x%2B1%29\" = 4 - 2
\n" ); document.write( "\"sqrt%283x%2B1%29\" = 2
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\n" ); document.write( "Square both sides and you have:
\n" ); document.write( "3x + 1 = 4
\n" ); document.write( "3x = 4 - 1
\n" ); document.write( "3x = 3
\n" ); document.write( "x = 3/3
\n" ); document.write( "x = 1
\n" ); document.write( ":
\n" ); document.write( "Substitute +1 for x in the original equation to prove our solution
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