document.write( "Question 903679: A TEST INVOLVING ONE POPULATION PROPORTION:
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document.write( "a recent article in USA today reported that job awaits only one in three new college graduates. the major reasons given were an overabundance of college graduates and a weak economy. A survey of 200 recent graduates from your school revealed that 80 students had jobs. at the .02 significant level we can conclude that a larger proportion of graduates at your school have jobs? \n" );
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Algebra.Com's Answer #548218 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Ho: p = .33 \n" ); document.write( "Ha: p > .33 (claim) \n" ); document.write( "----------------------------------------- \n" ); document.write( "sample proportion = p-hat = 80/200 = 2/5 = .4 \n" ); document.write( "--- \n" ); document.write( "test stat:: z(x > .4) = (0.4-0.33)/sqrt[(1/3)(2/3)/200] = .07/.03= 2.33 \n" ); document.write( "----- \n" ); document.write( "p-value = P(z > 2.33) = 1 - P( Z < 2.33) = 1 - .99 = .01\r \n" ); document.write( "\n" ); document.write( "Since the p-value is less than .02, reject Ho. \n" ); document.write( "The test results support the claim. \n" ); document.write( " \n" ); document.write( " |