document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549986>Question 549986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A truck traveling at an average rate of 45 miles per hour leaves a rest stop. Fifteen minutes later a car traveling at an average rate of 60 miles per hour leaves the same rest stop traveling the same route. How long will it take for the car to catch up with the truck? Thanks!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548217 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> gaining speed 60 -45= 15 mph<BR>\n" );
document.write( "headstart  45*0.25 =11.25 miles NOT 15<BR>\n" );
document.write( "time to catch up 11.25/15=0.75 hours<BR>\n" );
document.write( "time to catch up =45 minutes<BR>\n" );
document.write( "distance to meeting 0.75*60=45 miles\r<BR>\n" );
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