document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903658>Question 903658</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.when 5 is subtracted from two-thirds of a number. The result is the same when 25 is added to one-sixth of the number.find the number.<BR>\n" );
document.write( "a.58<BR>\n" );
document.write( "b.60<BR>\n" );
document.write( "c.62<BR>\n" );
document.write( "d.64<BR>\n" );
document.write( "e.66<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548206 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one problem  at  a time  <BR>\n" );
document.write( "limit 5 question per 24 hours<BR>\n" );
document.write( "no duplicates or similar problems\r<BR>\n" );
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document.write( "(2/3)n-5=25+n/6<BR>\n" );
document.write( "4/6*n-1/6n=30<BR>\n" );
document.write( "3/6n=30<BR>\n" );
document.write( "1/2n=30<BR>\n" );
document.write( "n=60<BR>\n" );
document.write( "check<BR>\n" );
document.write( "2/3*60-5=25+60/6<BR>\n" );
document.write( "40-5=25+10<BR>\n" );
document.write( "35=35<BR>\n" );
document.write( "ok\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );