document.write( "Question 903656: 1. The sum of three consecutive odd integers is 57. What is the sum if each of the numbers is doubled?
\n" ); document.write( "a.108
\n" ); document.write( "b.110
\n" ); document.write( "c.112
\n" ); document.write( "d.114
\n" ); document.write( "e.116\r
\n" ); document.write( "\n" ); document.write( "2.four times a number added to 8 gives 20. What is the number?
\n" ); document.write( "a.3
\n" ); document.write( "b.6
\n" ); document.write( "c.9
\n" ); document.write( "d.12
\n" ); document.write( "e.15
\n" ); document.write( "

Algebra.Com's Answer #548201 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
I would logically guess, 114, without trying to do algebra in symbols and equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2n+1, 2n+3, 2n+5.
\n" ); document.write( "Their sum \"2n%2B1%2B2n%2B3%2B2n%2B5=57\"
\n" ); document.write( "\"6n%2B9=57\"
\n" ); document.write( "\"6n=48\"
\n" ); document.write( "\"n=48%2F6\"
\n" ); document.write( "\"n=8\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The original numbers would be 17, 19, 21.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "NOW, if those are doubled and then summed:
\n" ); document.write( "\"2%2817%2B19%2B21%29\"
\n" ); document.write( "\"2%2A57\"
\n" ); document.write( "\"highlight%28114%29\"
\n" ); document.write( "
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