document.write( "Question 903644: The dimensions of a rectangle are such that its length is
\n" ); document.write( "9
\n" ); document.write( "in. more than its width. If the length were doubled and if the width were decreased by
\n" ); document.write( "4
\n" ); document.write( "in., the area would be increased by
\n" ); document.write( "168 \r
\n" ); document.write( "\n" ); document.write( "in.2.
\n" ); document.write( "What are the length and width of the rectangle?
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Algebra.Com's Answer #548193 by lwsshak3(11628)\"\" \"About 
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The dimensions of a rectangle are such that its length is
\n" ); document.write( "9in. more than its width. If the length were doubled and if the width were decreased by 4in., the area would be increased by 168 in^2.What are the length and width of the rectangle?
\n" ); document.write( "***
\n" ); document.write( "let x=original width of rectangle
\n" ); document.write( "x+9=original length of rectangle
\n" ); document.write( "2(x+9)=new length of rectangle
\n" ); document.write( "x-4=new width of rectangle
\n" ); document.write( "area=length*width
\n" ); document.write( "..
\n" ); document.write( "2(x+9)(x-4)-x(x+9)=168
\n" ); document.write( "2(x^2+5x-36)-x^2-9x=168
\n" ); document.write( "2x^2+10x-72-x^2-9x=168
\n" ); document.write( "x^2+x-240=0
\n" ); document.write( "(x+16)(x-15)=0
\n" ); document.write( "x=-16 (reject)
\n" ); document.write( "or
\n" ); document.write( "x=15
\n" ); document.write( "x+9=24
\n" ); document.write( "width of rectangle=15 in
\n" ); document.write( "length of rectangle=24 in
\n" ); document.write( "
\n" );