document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903590>Question 903590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joan is 7 years older than twice her son Rommel. Five years ago she was 3 years less than thrice as old as her son. Find the present age of Rommel.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548178 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> J = 2R + 7<BR>\n" );
document.write( "J-5 = 3(R-5) - 3<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "J-5 = 3R-15-3<BR>\n" );
document.write( "J-5 = 3R-18<BR>\n" );
document.write( "Add 5 to each side<BR>\n" );
document.write( "J = 3R - 13<BR>\n" );
document.write( "Take that value of J and substitute it for J in the first equation<BR>\n" );
document.write( "J = 2R + 7<BR>\n" );
document.write( "3R-13 = 2R+7<BR>\n" );
document.write( "Subtract 2R from each side<BR>\n" );
document.write( "R - 13 = 7<BR>\n" );
document.write( "Add 13 to each side<BR>\n" );
document.write( "R = 20<BR>\n" );
document.write( "If Rommel is 20, then Joan is 47.<br><BR>\n" );
document.write( "Prove it:<BR>\n" );
document.write( "Five years ago (47-5=42) she was 3 years less than thrice as old as her son 20-5=15).<BR>\n" );
document.write( "42 = (3*15)-3<BR>\n" );
document.write( "42=45-3<BR>\n" );
document.write( "42=42 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );