document.write( "Question 903592: Two cyclists , Elisa May and Dhey-dhey, start at the same time from opposite ends of a course that is 45 miles long. Elisa May is riding at 14mph and Dhey-dhey at 16mph. How long after they begin will they meet? \n" ); document.write( "
Algebra.Com's Answer #548169 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Two cyclists , Elisa May and Dhey-dhey, start at the same time from opposite ends of a course that is 45 miles long. Elisa May is riding at 14mph and Dhey-dhey at 16mph. How long after they begin will they meet? \n" ); document.write( "----- \n" ); document.write( "EM DATA: \n" ); document.write( "rate = 14 mph ; distance = x miles ; time = d/r = x/14 hrs \n" ); document.write( "------ \n" ); document.write( "DD DATA: \n" ); document.write( "rate = 16 mph ; distance = 45-x miles ; time = d/r = (45-x)/16 \n" ); document.write( "--------- \n" ); document.write( "Equation: \n" ); document.write( "time = time \n" ); document.write( "x/14 = (45-x)/16 \n" ); document.write( "---------- \n" ); document.write( "16x = 14*45-14x \n" ); document.write( "---- \n" ); document.write( "30x = 14*45 \n" ); document.write( "x = (3/2)14 \n" ); document.write( "x = 21 miles \n" ); document.write( "------ \n" ); document.write( "Ans:: time = x/14 = 21/14 = 3/2 = 1.5 hours \n" ); document.write( "-------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------------- \n" ); document.write( " |