document.write( "Question 903489: Running at an average rate of 5 meters per second, a sprinter ran to the end of a track. The sprinter then jogged back to the starting point at an average rate of 2 meters per second. The total time for the sprint and the jog back was 2 minutes 27 seconds. Find the length of the track. \n" ); document.write( "
Algebra.Com's Answer #548166 by ankor@dixie-net.com(22740)\"\" \"About 
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Running at an average rate of 5 meters per second, a sprinter ran to the end of a track.
\n" ); document.write( " The sprinter then jogged back to the starting point at an average rate of 2 meters per second.
\n" ); document.write( " The total time for the sprint and the jog back was 2 minutes 27 seconds.
\n" ); document.write( " Find the length of the track.
\n" ); document.write( ":
\n" ); document.write( "let d = the length of the track
\n" ); document.write( ":
\n" ); document.write( "Change 2 min 27 sec to 147 sec
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "run time + jog time = 147 sec
\n" ); document.write( "\"d%2F5\" + \"d%2F2\" = 147
\n" ); document.write( "multiply by 10 to get rid of the deliminators
\n" ); document.write( "2d + 5d = 10(147)
\n" ); document.write( "7d = 1470
\n" ); document.write( "d = 1470/7
\n" ); document.write( "d = 210 meters
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check it, find the actual time each way
\n" ); document.write( "210/5 = 42 sec
\n" ); document.write( "210/2 = 105 sec
\n" ); document.write( "-------------
\n" ); document.write( "total: 147 sec \n" ); document.write( "
\n" );