document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902871>Question 902871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sydney left the study group traveling 6 mph. Then, 3 hours later, Monique left traveling the same direction at 12 mph. How long until Monique catches up with Sydney? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548129 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> gaining speed 12 -6= 6 mph<BR>\n" );
document.write( "headstart  6*3 =18 miles<BR>\n" );
document.write( "time to catch up 18/6=3 hours<BR>\n" );
document.write( "distance to meeting 3*12=36 miles<BR>\n" );
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