document.write( "Question 902803: At 6 A.M. a snowplow, traveling at a constant speed, begins to clear a highway leading out of town. At 8 A.M. an automobile begins traveling the highway at a speed of 35 mi/hr and reaches the plow 20 minutes later. Find the speed of the snowplow. \n" ); document.write( "
Algebra.Com's Answer #548124 by richwmiller(17219)\"\" \"About 
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6am
\n" ); document.write( "8am - 8:20 20/60=1/3
\n" ); document.write( "snow plow r*t\r
\n" ); document.write( "\n" ); document.write( "35 mph
\n" ); document.write( "35*1/3=11 2/3 miles
\n" ); document.write( "r*t=d\r
\n" ); document.write( "\n" ); document.write( "plow x mph for 2 hours hours went y miles
\n" ); document.write( "car 35 mph 35-p=g miles gaining
\n" ); document.write( "y/g=1/3 hours\r
\n" ); document.write( "\n" ); document.write( "r*(7/3)=35/3
\n" ); document.write( "r*7=35
\n" ); document.write( "r=5 mph for snow plow\r
\n" ); document.write( "\n" ); document.write( "(r+g)*1/3=11 2/3
\n" ); document.write( "35/3=11 2/3
\n" ); document.write( "r+g=35
\n" ); document.write( "5+g=35
\n" ); document.write( "g=30
\n" ); document.write( "30/3=10 miles ahead check 5*2=10
\n" ); document.write( "distance was 11/2/3 m
\n" ); document.write( "snow plow went 5 mph\r
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