document.write( "Question 903534: With the current, you can canoe 104 miles in 4 hours. Against the same current, you can canoe only 3/4 of this distance in 6 Hours. Find your rate in still water and the rate of the current. What is the rate of the canoe in still water? \n" ); document.write( "
Algebra.Com's Answer #548114 by lwsshak3(11628)\"\" \"About 
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With the current, you can canoe 104 miles in 4 hours. Against the same current, you can canoe only 3/4 of this distance in 6 Hours. Find your rate in still water and the rate of the current. What is the rate of the canoe in still water?
\n" ); document.write( "***
\n" ); document.write( "let x=rate of canoe in still water
\n" ); document.write( "let c=rate of current
\n" ); document.write( "x+c=rate of canoe with current
\n" ); document.write( "x-c=rate of canoe against current
\n" ); document.write( "travel time*rate=distance
\n" ); document.write( "..
\n" ); document.write( "4(x+c)=104
\n" ); document.write( "6(x-c)=(3/4)*104=78
\n" ); document.write( "..
\n" ); document.write( "4x+4c=104
\n" ); document.write( "6x-6c=78
\n" ); document.write( "..
\n" ); document.write( "12x+12c=312 (mult. by 3)
\n" ); document.write( "12x-12c=156 (mult. by 2)
\n" ); document.write( "add
\n" ); document.write( "24x=468
\n" ); document.write( "x=19.5
\n" ); document.write( "4c=104-4x=26
\n" ); document.write( "c=6.5
\n" ); document.write( "rate of canoe in still water=19.5 mph
\n" ); document.write( "rate of current=6.5 mph
\n" ); document.write( " \n" ); document.write( "
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