document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903211>Question 903211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A large grain silo is to be constructed in the shape of a circular cylinder with a hemisphere attached to the top (see the figure). The diameter of the silo is to be 30 feet, but the height is yet to be determined. Find the height h of the silo that will result in a capacity of 13,725&#960; ft3.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548093 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A large grain silo is to be constructed in the shape of a circular cylinder with a hemisphere attached to the top (see the figure).<BR>\n" );
document.write( " The diameter of the silo is to be 30 feet, but the height is yet to be determined.<BR>\n" );
document.write( " Find the height h of the silo that will result in a capacity of 13,725&#960; ft3.<BR>\n" );
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document.write( "From the information given, we know the radius of the silo = 15 ft<BR>\n" );
document.write( "let h = the height of the cylinder portion of the silo (w/o the hemisphere)<BR>\n" );
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document.write( "The total volume equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A15%5E2%2Ah ALIGN=MIDDLE  ALT=\"pi%2A15%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A15%5E3 ALIGN=MIDDLE  ALT=\"pi%2A15%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=13725%2Api ALIGN=MIDDLE  ALT=\"13725%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "simplify, divide equation by pi<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%5E2%2Ah ALIGN=MIDDLE  ALT=\"15%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%5E3 ALIGN=MIDDLE  ALT=\"15%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=13725 ALIGN=MIDDLE  ALT=\"13725\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Factor out 15^2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%5E2%28h+%2B+2%2F3+%2A+15%29 ALIGN=MIDDLE  ALT=\"15%5E2%28h+%2B+2%2F3+%2A+15%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 13725<BR>\n" );
document.write( "divide both side by 15^2<BR>\n" );
document.write( "h + 10 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=13725%2F15%5E2 ALIGN=MIDDLE  ALT=\"13725%2F15%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "h + 10 = 61<BR>\n" );
document.write( "h = 51 ft is the height of the cylinder portion of the silo<BR>\n" );
document.write( "Add the height of the hemisphere<BR>\n" );
document.write( "51 + 15 = 66 ft is the height of the silo<BR>\n" );
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