document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903446>Question 903446</A>: <I><SPAN STYLE=\"word-break: break-all;\"> on a map, a nature-center  trail is 9.3 cm. If the scale is 3 cm to 44 cm, what is the actual length of the trail. Round to the nearest tenth if necessary  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548054 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> on a map, a nature-center  trail is 9.3 cm. If the scale is 3 cm to 44 cm, what is the actual length of the trail.<BR>\n" );
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document.write( "3 cm --> 44 cm<BR>\n" );
document.write( "9.3 = 3.1 times 3<BR>\n" );
document.write( "--> 3.1 time 44 = 136.4 cms<BR>\n" );
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document.write( "Or,<BR>\n" );
document.write( "3/9.3 = 44/d<BR>\n" );
document.write( "3d = 409.2<BR>\n" );
document.write( "d = 136.4 cm<BR>\n" );
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document.write( "That's not a very long trail.  2 steps should do it.<BR>\n" );
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