document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903371>Question 903371</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider a large clothing shop in Sydney. Suppose it is known that the number of business suits sold per day is normally distributed with a mean, &#956; = 20 and standard deviation, &#963; = 10.  Mr Wood is employed to sell business suits. The number of business suits he sells each day for 25 days is recorded and the mean number per day calculated.  \r<BR>\n" );
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document.write( "What is the probability that Mr Wood's average daily sales will be between 15 and 25 business suits?  (4 dp) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #548048 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=548048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z = (15-20)/10/sqrt(25) = -5/2<BR>\n" );
document.write( "z = (25-20)/10/sqrt(25) = 5/2<BR>\n" );
document.write( "P(-5/2 < z < 5/2) = normalcdf(-2.5, 2.5) </SPAN>\n" );
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