document.write( "Question 903448: A rectangle is 4 times as long as it is wide. The area is 144 square feet. What is the perimeter of the rectangle?
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Algebra.Com's Answer #548033 by Stitch(470)\"\" \"About 
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Let L = the length of the rectangle
\n" ); document.write( "Let W = the Width of the rectangle
\n" ); document.write( "The equation for the Area of a rectangle is A = L x W
\n" ); document.write( "The equation for the perimeter of a rectangle is P = 2L + 2W
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\n" ); document.write( "Equation 1: \"144+=+L+%2A+W\"
\n" ); document.write( "Equation 2: \"L+=+4W\" (The rectangle is 4 times as long as it is wide)
\n" ); document.write( "Equation 3: \"P+=+2L+%2B+2W\"
\n" ); document.write( "Note that equation 2 is already solved for L.
\n" ); document.write( "Plug (4W) into equation 1 for L
\n" ); document.write( "Equation 1: \"144+=+L+%2A+W\"
\n" ); document.write( "\"144+=+%284W%29+%2A+W\"
\n" ); document.write( "Combine like terms
\n" ); document.write( "\"144+=+4W%5E2\"
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "\"36+=+W%5E2\"
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( "\"sqrt%2836%29+=+sqrt%28W%5E2%29\"
\n" ); document.write( "\"highlight%286+=+W%29\"
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\n" ); document.write( "Now plug 6 into equation 2 for W
\n" ); document.write( "Equation 2: \"L+=+4W\"
\n" ); document.write( "\"L+=+4%2A%286%29\"
\n" ); document.write( "\"highlight_green%28L+=+24%29\"
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\n" ); document.write( "Now Plug L=24, and W=6 into equation 3
\n" ); document.write( "Equation 3: \"P+=+2L+%2B+2W\"
\n" ); document.write( "\"P+=+2%2A%2824%29+%2B+2%2A%286%29\"
\n" ); document.write( "Simplify
\n" ); document.write( "\"P+=+48+%2B+12\"
\n" ); document.write( "\"highlight%28P+=+60%29\"
\n" ); document.write( "The perimeter is 60ft
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