document.write( "Question 76364: I would like help completely factoring 28ab^2c-56a Thanks! \n" ); document.write( "
Algebra.Com's Answer #54802 by bucky(2189)\"\" \"About 
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28ab^2c-56a
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\n" ); document.write( "The first thing to do is to look at the constants in each of the two terms to see if they
\n" ); document.write( "have any common factors that can be pulled out. In this problem 2 would be a common
\n" ); document.write( "factor of both 28 and 56. You can go further and say that 7 is a common factor of both
\n" ); document.write( "28 and 56. And if you continue along this line you will see that 14 is a common factor,
\n" ); document.write( "and finally 28 is a common factor of both 28 and 56. If you pull the 28 out as a common
\n" ); document.write( "factor the result is:
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\n" ); document.write( "28*(ab^2c - 2a)
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\n" ); document.write( "As a check, notice that if you perform this distributed multiplication you get back to
\n" ); document.write( "the original polynomial of the problem.
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\n" ); document.write( "Now look at the terms in the parentheses. Are there are any common factors that appear
\n" ); document.write( "in both terms. Yes ... the common variable is \"a\". Pull the \"a\" out of both the terms
\n" ); document.write( "and you get:
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\n" ); document.write( "28*a*(b^2c - 2)
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\n" ); document.write( "There are no more common variables inside the parentheses, so this is as far as you can
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\n" ); document.write( "So the answer to this problem is that the factored form is 28a(b^2c - 2). Again, if you
\n" ); document.write( "perform this distributed multiplication you get back to the original polynomial.
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\n" ); document.write( "Hope this helps you to see a basic method of factoring polynomials. \n" ); document.write( "
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