document.write( "Question 903257: Lillian had $15000 invested in two accounts one paying 9% simple interest and one paying 10% simple interest. how much was invested in each account it the interest after i yr is 1432? \n" ); document.write( "

Algebra.Com's Answer #548014 by richwmiller(17219) $\"\"$ $\"About$

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We know the total amount of money invested. $15000
\n" ); document.write( "x+y=15000,
\n" ); document.write( "We know that the total interest for the year for the two accounts is $1432
\n" ); document.write( "0.09*x+0.1*y=1432
\n" ); document.write( "x=15000-y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.09*(15000-y)+0.1*y=1432
\n" ); document.write( "We multiply out
\n" ); document.write( "1350-0.09y+0.1*y=1432
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.01*y=82
\n" ); document.write( "Isolate y
\n" ); document.write( "y=8200 at 10%
\n" ); document.write( "x=15000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=6800 at 9%
\n" ); document.write( "We check
\n" ); document.write( "0.09*6800+0.1*8200=1432
\n" ); document.write( "612+820=1432
\n" ); document.write( "1432=1432
\n" ); document.write( "Since this statement is TRUE and neither amount is negative then it is ok
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