document.write( "Question 903411: two workmen can paint a house together in 6 and 1/3 days. in how many days can each paint it alone if it takes one of them two days longer than the other? \n" ); document.write( "
Algebra.Com's Answer #547990 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 1/x+1/(x+2)=1/6.333 \n" ); document.write( "(6.333*x*(x+2))/x+(6.333*x*(x+2))/(x+2)=(6.333*x*(x+2))/6.333 \n" ); document.write( "(6.333*(x+2))+6.333*x=x*(x+2) \n" ); document.write( "6.333*x+12.666+6.333*x=x^2+2*x \n" ); document.write( "12.666*x+12.666=x^2+2*x \n" ); document.write( "x^2+-10.666*x-12.666=0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "11.7444654331128 days \n" ); document.write( "13.7444654331128 days \n" ); document.write( "check \n" ); document.write( "a=11.7444654 days \n" ); document.write( "b=13.7444654 days \n" ); document.write( "1/a+1/b=1/x \n" ); document.write( "1/11.7444654+1/13.7444654=1/x \n" ); document.write( "1/11.7444654+1/13.7444654=1/6.333 \n" ); document.write( "1/x=1/6.333 \n" ); document.write( "x=6.333 days working together\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |