document.write( "Question 903414: If in an online processing web based application 200 users who had to load a file had a mean time of 120 secs in loading a file with a standard deviation of 10 secs, then the worst case (ie “lowest” ) estimate for the number of users who have waited for more than 100 secs but less than 140 secs is \n" ); document.write( "
Algebra.Com's Answer #547977 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If in an online processing web based application 200 users who had to load a file had a mean time of 120 secs in loading a file with a standard deviation of 10 secs, then the worst case (ie “lowest” ) estimate for the number of users who have waited for more than 100 secs but less than 140 secs is \n" ); document.write( "---------------- \n" ); document.write( "z(100) = (100-120)/10 = -2 \n" ); document.write( "z(140) = (140-120)/10 = 2 \n" ); document.write( "------ \n" ); document.write( "P(100<= x <=140) = P(-2<= z <=2) = normalcdf(-2,2) = 0.9545 \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------ \n" ); document.write( " |