document.write( "Question 903414: If in an online processing web based application 200 users who had to load a file had a mean time of 120 secs in loading a file with a standard deviation of 10 secs, then the worst case (ie “lowest” ) estimate for the number of users who have waited for more than 100 secs but less than 140 secs is \n" ); document.write( "
Algebra.Com's Answer #547977 by stanbon(75887)\"\" \"About 
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If in an online processing web based application 200 users who had to load a file had a mean time of 120 secs in loading a file with a standard deviation of 10 secs, then the worst case (ie “lowest” ) estimate for the number of users who have waited for more than 100 secs but less than 140 secs is
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\n" ); document.write( "z(100) = (100-120)/10 = -2
\n" ); document.write( "z(140) = (140-120)/10 = 2
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\n" ); document.write( "P(100<= x <=140) = P(-2<= z <=2) = normalcdf(-2,2) = 0.9545
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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