document.write( "Question 76391: what is the solution of 1+3logx=logx+logxto the 3rd power \n" ); document.write( "

Algebra.Com's Answer #54796 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( " $\"1%2B3log%28x%29+=+log%28x%29%2Blog%28x%29%5E3\"$ Apply the law of exponents for logarithms to the left-hand side.
\n" ); document.write( " $\"1%2Blog%28x%29%5E3+=+log%28x%29%2Blog%28x%29%5E3\"$ Subtract $\"log%28x%29%5E3\"$ from both sides.
\n" ); document.write( " $\"1+=+log%28x%29\"$ Rewrite the this in exponential form.
\n" ); document.write( " $\"x+=+10%5E1\"$
\n" ); document.write( "Solution:
\n" ); document.write( "x = 10 \n" ); document.write( "

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