document.write( "Question 903387: A man left A at 6:00 am expecting to reach B at 9:00 am. But after walking one hour, he was delayed for half an hour and so he had to increase his rate by 1 mile per hour to reach B at 9:00 am. Find his speed before the delay and the distance between A and B. \n" ); document.write( "
Algebra.Com's Answer #547952 by josgarithmetic(39617)\"\" \"About 
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______________rate_________time_________distance
\n" ); document.write( "_______________r___________3____________r*3=d
\n" ); document.write( "before interr___r___________1_____________r*1
\n" ); document.write( "after interr____r+1_________1_____________(r+1)*1
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\n" ); document.write( "Sum of before and after interruption d distance.
\n" ); document.write( "\"r%2B%28r%2B1%29=d\"
\n" ); document.write( "\"2r%2B1=d\"\r
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\n" ); document.write( "\n" ); document.write( "Expected regular travel \"r%2A3=d\";\r
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\n" ); document.write( "\n" ); document.write( "\"2r%2B1=r%2A3\", equating the distance
\n" ); document.write( "\"1=1%2Ar\"
\n" ); document.write( "\"highlight%28r=1%29\"-----walking speed, before interruption.\r
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\n" ); document.write( "\n" ); document.write( "\"r%2A3=d\"
\n" ); document.write( "\"d=3r\"
\n" ); document.write( "\"d=3%2A1\"
\n" ); document.write( "\"highlight%28d=3%29\"-----travel distance.
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