document.write( "Question 903387: A man left A at 6:00 am expecting to reach B at 9:00 am. But after walking one hour, he was delayed for half an hour and so he had to increase his rate by 1 mile per hour to reach B at 9:00 am. Find his speed before the delay and the distance between A and B. \n" ); document.write( "
Algebra.Com's Answer #547952 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! ______________rate_________time_________distance \n" ); document.write( "_______________r___________3____________r*3=d \n" ); document.write( "before interr___r___________1_____________r*1 \n" ); document.write( "after interr____r+1_________1_____________(r+1)*1 \n" ); document.write( "- \n" ); document.write( "- \n" ); document.write( "Sum of before and after interruption d distance. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Expected regular travel \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |