document.write( "Question 902444: An investment of $4600 is made at an annual simple interest rate of 6.8%. How much additional money must be invested at an annual simple interest rate of 9% so that the total interest earned is 8% of the total investment? \n" ); document.write( "
Algebra.Com's Answer #547943 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x+y=4600, \n" ); document.write( "0.09*x+0.068*y=0.08*4600 \n" ); document.write( "0.09*x+0.068*y=368 \n" ); document.write( "x=4600-y \n" ); document.write( "0.09*(4600-y)+0.068*y=368 \n" ); document.write( "414-0.09y+0.068*y=368 \n" ); document.write( "-0.022*y=-46 \n" ); document.write( "y=2090.90909 at 6.8% \n" ); document.write( "x=4600-y \n" ); document.write( "x=2509.09091 at 9% \n" ); document.write( "check \n" ); document.write( "0.09*2509.09091+0.068*2090.90909=0.08*4600 \n" ); document.write( "225.818182+142.181818=368 \n" ); document.write( "368.0=368 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |