document.write( "Question 902444: An investment of $4600 is made at an annual simple interest rate of 6.8%. How much additional money must be invested at an annual simple interest rate of 9% so that the total interest earned is 8% of the total investment? \n" ); document.write( "
Algebra.Com's Answer #547943 by richwmiller(17219)\"\" \"About 
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x+y=4600,
\n" ); document.write( "0.09*x+0.068*y=0.08*4600
\n" ); document.write( "0.09*x+0.068*y=368
\n" ); document.write( "x=4600-y
\n" ); document.write( "0.09*(4600-y)+0.068*y=368
\n" ); document.write( "414-0.09y+0.068*y=368
\n" ); document.write( "-0.022*y=-46
\n" ); document.write( "y=2090.90909 at 6.8%
\n" ); document.write( "x=4600-y
\n" ); document.write( "x=2509.09091 at 9%
\n" ); document.write( "check
\n" ); document.write( "0.09*2509.09091+0.068*2090.90909=0.08*4600
\n" ); document.write( "225.818182+142.181818=368
\n" ); document.write( "368.0=368
\n" ); document.write( "ok
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