document.write( "Question 903361: In changing a $5, Marge received 9 more dimes than nickels and 7 fewer quarters than dimes. How many of each coin did she receive?\r
\n" ); document.write( "\n" ); document.write( "nickels=x
\n" ); document.write( "dimes=9+x
\n" ); document.write( "quarters= x-7 = 9+x-7 = x-2\r
\n" ); document.write( "\n" ); document.write( "x+9+x+x-2=?
\n" ); document.write( "3x+7=?\r
\n" ); document.write( "\n" ); document.write( "Not sure what the number should be that the equation equals. Would it be 500?
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Algebra.Com's Answer #547942 by MathTherapy(10555) $\"\"$ $\"About$

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In changing a $5, Marge received 9 more dimes than nickels and 7 fewer quarters than dimes. How many of each coin did she receive?\r
\n" ); document.write( "\n" ); document.write( "nickels=x
\n" ); document.write( "dimes=9+x
\n" ); document.write( "quarters= x-7 = 9+x-7 = x-2\r
\n" ); document.write( "\n" ); document.write( "x+9+x+x-2=?
\n" ); document.write( "3x+7=?\r
\n" ); document.write( "\n" ); document.write( "Not sure what the number should be that the equation equals. Would it be 500?
\n" ); document.write( "


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document.write( "You can use one variable, as you did. 
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document.write( "Number of nickels: x
\n" );
document.write( "Number of dimes: 9 + x
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document.write( "Number of quarters: 9 + x - 7, or x + 2, NOT x - 2 as you stated\r
\n" );
document.write( "\n" );
document.write( "Now, the equation becomes: , or
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document.write( " -------- MULTIPLYING by 20 to get rid of decimals
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document.write( "The first equation would equal 500 if you multiply it by 100, but that's unnecessary
\n" );
document.write( "since multiplying by 20 does the job of getting rid of the decimals
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document.write( "Solve for x, the number of nickels.
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document.write( "Add 9 to x to get the number of dimes
\n" );
document.write( "Add 2 to x to get the number of quarters. \n" );
document.write( "

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