document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903251>Question 903251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lee Ann Sphar wants to mix tea worth 2 cents per oz with 100 oz of tea worth 5 cents per oz to make a mixture worth 3 cents per oz.  How much 2 cents tea should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547941 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.02*x+0.05*100=0.03(100+x)<BR>\n" );
document.write( "0.02*x+5=3+0.03x<BR>\n" );
document.write( "0.02x-0.03x=3-5<BR>\n" );
document.write( "-0.01x=-2<BR>\n" );
document.write( "x=200 oz of 2cent is added to 100 oz of 5cent  to get  300 oz  at 3cent<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.02*200+0.05*100=0.03(100+200)<BR>\n" );
document.write( "4+5=0.03(300)<BR>\n" );
document.write( "9=9<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );