document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903327>Question 903327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 4% salt solution must be mixed with 25 gallons of a 6% solution to obtain a 5% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547903 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.04*x+0.06*25=0.05(25+x)<BR>\n" );
document.write( "0.04*x+1.5=1.25+0.05x<BR>\n" );
document.write( "0.04x-0.05x=1.25-1.5<BR>\n" );
document.write( "-0.01x=-0.25<BR>\n" );
document.write( "x=25 gallons of 4% is added to 25 gallons of 6% to get  50 gallons  at 5%<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.04*25+0.06*25=0.05(25+25)<BR>\n" );
document.write( "1+1.5=0.05(50)<BR>\n" );
document.write( "2.5=2.5<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );