document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903315>Question 903315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many different cash amounts can be made by choosing 4 coins from a penny, nickel, dime, quarter, loonie and a tonnie?\r<BR>\n" );
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document.write( "Would this be a combination?\r<BR>\n" );
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document.write( "I.E.        6C4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547899 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes, then you evaluate that to get\r<BR>\n" );
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document.write( "n C r = (n!)/(r!(n-r)!)\r<BR>\n" );
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document.write( "6 C 4 = (6!)/(4!*(6-4)!)\r<BR>\n" );
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document.write( "6 C 4 = (6!)/(4!*2!)\r<BR>\n" );
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document.write( "6 C 4 = (6*5*4!)/(4!*2!)\r<BR>\n" );
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document.write( "6 C 4 = (6*5)/(2!)\r<BR>\n" );
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document.write( "6 C 4 = (6*5)/(2*1)\r<BR>\n" );
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document.write( "6 C 4 = (30)/(2)\r<BR>\n" );
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document.write( "6 C 4 = 15\r<BR>\n" );
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document.write( "So there are 15 combinations (order doesn't matter) </SPAN>\n" );
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