document.write( "Question 903199: Deedee invested $2000, part at 7% per annum and the rest at 8% per annum. After one year, the interest earned on the 7% investment was $50 more than the interest on the 8% investment. How much (money) did she invest a each rate?\r
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Algebra.Com's Answer #547852 by richwmiller(17219)\"\" \"About 
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x+y=2000,
\n" ); document.write( ".07x=.08y+50,
\n" ); document.write( "x+y=2000
\n" ); document.write( ".07(2000-y)-.08y=50\r
\n" ); document.write( "\n" ); document.write( "investment
\n" ); document.write( "x=1400 at 7%, y=600 at 8%\r
\n" ); document.write( "\n" ); document.write( "interest earned
\n" ); document.write( "98-48=50
\n" ); document.write( "$146 total interest
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