document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76386>Question 76386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a circular tabletop has a circumference of 37 feet. What are the approximate measures of the diameter of the tabletop? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54785 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54785\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> CIR=2*PI*R<BR>\n" );
document.write( "37=2*3.14*R<BR>\n" );
document.write( "37=6.28R<BR>\n" );
document.write( "R=37/6.28<BR>\n" );
document.write( "R=5.89 IS THE RADIUS THUS THE DIAMETER IS <BR>\n" );
document.write( "2*5.89=11.78 FEET. </SPAN>\n" );
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