document.write( "Question 76371: Find two consecutive intergers such that twice the first interger plus the second interger equals 46. \n" ); document.write( "

Algebra.Com's Answer #54784 by rmromero(383) $\"\"$ $\"About$

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document.write( "Find two consecutive intergers such that twice the first interger plus the second interger equals 46.\r
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document.write( "What is asked in the problem?\r
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document.write( "  find two consecutive integers\r
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document.write( "Given:\r
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document.write( "  twice the first plus the second integer equals 46\r
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document.write( "Representation:
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document.write( "Let     n be the first integer
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document.write( "    n + 1 be the second integer \r
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document.write( "Equation:
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document.write( "   2n + n + 1 = 46                combine like terms
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document.write( "       3n + 1 = 46                Subtract 1 both sides 
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document.write( "           3n = 45                divide 3 both sides  
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document.write( "            n = 15  First integer\r
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document.write( "  n + 1 = 15 + 1
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document.write( "        = 16        Second integer\r
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document.write( "CHecking :\r
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document.write( "   2(15) + 16 = 46
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document.write( "     30  + 16 = 46
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document.write( "           46 = 46  ----> True\r
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document.write( "Visit my website:
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document.write( "http://onlinemathtutorial.tripod.com
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document.write( "Thanks \n" );
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