document.write( "Question 903143: if you add jasons and heathers age you get 51. jason is 9 years younger then twice heathers age. find out both ages.\r
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Algebra.Com's Answer #547828 by AlgebraLady88(44)\"\" \"About 
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If you add Jason and Heather's age, you get 51.\r
\n" ); document.write( "\n" ); document.write( "Let's write this algebraically.
\n" ); document.write( "That would be J+H = 51\r
\n" ); document.write( "\n" ); document.write( "Jason is 9 years younger than twice Heather's age.We can also write this algebraically.\r
\n" ); document.write( "\n" ); document.write( "J= 2H -9 \r
\n" ); document.write( "\n" ); document.write( "Now , we have two equations : J+H= 51 and J= 2H-9\r
\n" ); document.write( "\n" ); document.write( "We can focus on finding out either Heather or Jason's age first. Finding one will help us find the other one, so order does not matter. For this example, I will find out Heather's age first.\r
\n" ); document.write( "\n" ); document.write( "From the equation J+H= 51 , I get J= 51-H\r
\n" ); document.write( "\n" ); document.write( "I substitute J= 51-H in the equation J= 2H-9\r
\n" ); document.write( "\n" ); document.write( "51-H = 2H-9
\n" ); document.write( "-H-2H=-9-51
\n" ); document.write( "-3H =-60
\n" ); document.write( "(Divide both sides with -3) gives us H= 20\r
\n" ); document.write( "\n" ); document.write( "If Heather is 20, Jason is 31 as both added up gives us 51.\r
\n" ); document.write( "\n" ); document.write( "Let's check. Twice Heather's age is 40. At 31, Jason is 9 years younger than twice Heather's age.
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