document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76371>Question 76371</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive intergers such that twice the first interger plus the second interger equals 46. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54782 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X+(X+1)=46<BR>\n" );
document.write( "2X+X+1=46<BR>\n" );
document.write( "3X=46-1<BR>\n" );
document.write( "3X=45<BR>\n" );
document.write( "X=45/3<BR>\n" );
document.write( "X=15 ANSWER FOR THE FIRST INTERGER &<BR>\n" );
document.write( "15+1=16 FOR THE SECOND INTERGER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*15+16=46<BR>\n" );
document.write( "30+16=46<BR>\n" );
document.write( "46=46 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );