document.write( "Question 903095: A jazz group on tour has been drawing average crowds of 600 people. It is projected that for every $1 increase in the $11 ticket price, the average attendance will decrease by 60. At what ticket price will nightly receipts be $4,800? \n" ); document.write( "
Algebra.Com's Answer #547792 by AlgebraLady88(44)\"\" \"About 
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Ok, we are working with 600 people here. Wow, only 600 ? \r
\n" ); document.write( "\n" ); document.write( "Just kidding!\r
\n" ); document.write( "\n" ); document.write( "As we read further, we see that the ticket price is $11. Not bad for a ticket price. Then , we are told that for every $1 increase in the ticket price, the average attendance will decrease by 60. Ok, these customers really mean business!\r
\n" ); document.write( "\n" ); document.write( "We are asked what the ticket price would be for the nightly profit to be $4800.
\n" ); document.write( "Just for our own information, at $11 a ticket with 600 attendees, the profit would be $ 6600= 11*600 \r
\n" ); document.write( "\n" ); document.write( "So, if the ticket price went up $1 to $12, the nightly haul would be\r
\n" ); document.write( "\n" ); document.write( "$12 * 540 = $6480 (we now have 540 customers as 60 of the original 600 have decided to boycott the event) \r
\n" ); document.write( "\n" ); document.write( "At $13 a ticket, we now have 480 customers; the haul would be 13* 480 = $ 6240
\n" ); document.write( "At $14 a ticket, we now have 420 customers; the haul would be 14* 420 = $ 5880
\n" ); document.write( "At $15 a ticket, we now have 360 customers; the haul would be 15* 360 = $ 5400
\n" ); document.write( "At $16 a ticket, we now have 300 customers; the haul would be 16* 300 = $ 4800 Voila!\r
\n" ); document.write( "\n" ); document.write( "So, at $16 , the ticket sales would total $ 4800
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