document.write( "Question 76370: Find 3 consective even intergers such that the sum of twice the first and three times the second minus the third equals -38. \n" ); document.write( "
Algebra.Com's Answer #54778 by ankor@dixie-net.com(22740)\"\" \"About 
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\n" ); document.write( "Find 3 consecutive even integers,
\n" ); document.write( "x, (x+2), (x+4)
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\n" ); document.write( "the sum of twice the first and three times the second minus the third equals -38.
\n" ); document.write( "2x + 3(x+2) - (x+4) = - 38
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\n" ); document.write( "2x + 3x + 6 - x - 4 = -38
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\n" ); document.write( "2x + 3x - x = -38 - 6 + 4
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\n" ); document.write( "4x = -40
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\n" ); document.write( "x = -40/4
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\n" ); document.write( "x = -10
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\n" ); document.write( "The numbers: -10, -8, -6
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\n" ); document.write( "Check our solution of x = -10
\n" ); document.write( "sum of twice the first and three times the second minus the third equals -38.
\n" ); document.write( "2(-10) + 3(-8) - (-6) =
\n" ); document.write( "-20 - 24 + 6 = -38 \n" ); document.write( "
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