document.write( "Question 902810: Hello, This week we are learning how to graph the graphs of sin and cosine. I need help with graphing this one particular equation which says:y=5sin 3x
\n" );
document.write( "I know how to do the process, but I am having trouble dealing with the 3x part? Like I realize the 5 is my amplitude, the vertical shift is 0, and my period is 2pi/1, but I don't know what my phase shift is. Can anyone help? Thanks in advance. \n" );
document.write( "
Algebra.Com's Answer #547772 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The red line is the graph of 5sin(x) \n" ); document.write( "The green line is the graph of 5sin(3x) \n" ); document.write( "With the sin(3X), you are actually dividing the period by 3. \n" ); document.write( "An example of a phase shift would be sin(x-2) would shift the graph to the right 2 units.\r \n" ); document.write( "\n" ); document.write( "Here is a link to purplemath that has a helpful description on graphing trigonometric functions. \n" ); document.write( "http://www.purplemath.com/modules/grphtrig.htm \n" ); document.write( " |