document.write( "Question 903097: The oriental rug shown is 5 feet longer than it is wide. If the diagonal of the rug is 12 feet find its dimensions to the nearest tenth of a foot. \n" ); document.write( "
Algebra.Com's Answer #547763 by ewatrrr(24785)\"\" \"About 
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Using Pythagorean Theorem
\n" ); document.write( "(w+5)^2 + w^2 = 12^2
\n" ); document.write( "2w^2 + 10w - 119 = 0 (Tossing out the negative solution for unit measure)
\n" ); document.write( "w = 5.6 and L = 10.6 \"5.6%2B5\"
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"2x%5E2%2B10x%2B-119+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2810%29%5E2-4%2A2%2A-119=1052\".
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\n" ); document.write( " Discriminant d=1052 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-10%2B-sqrt%28+1052+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2810%29%2Bsqrt%28+1052+%29%29%2F2%5C2+=+5.60863737011343\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2810%29-sqrt%28+1052+%29%29%2F2%5C2+=+-10.6086373701134\"
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\n" ); document.write( " Quadratic expression \"2x%5E2%2B10x%2B-119\" can be factored:
\n" ); document.write( " \"2x%5E2%2B10x%2B-119+=+2%28x-5.60863737011343%29%2A%28x--10.6086373701134%29\"
\n" ); document.write( " Again, the answer is: 5.60863737011343, -10.6086373701134.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B10%2Ax%2B-119+%29\"
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