document.write( "Question 902943: A rectangle sign must have an area of 34 square yards. Its length must be 2 yards more than its width. Find the exact dimensions of the sign. \n" ); document.write( "
Algebra.Com's Answer #547747 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! Let L = length of the sign \n" ); document.write( "Let W = width of the sign \n" ); document.write( "Since you are given two unknowns, you will need two equations. \n" ); document.write( "Area(A) of a rectangle = Length x Width \n" ); document.write( "Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( "Given: A = 34 yds^2 \n" ); document.write( "Plug 34 into equation 1 for A \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( "Notice that equation 2 is already solved for L \n" ); document.write( "Plug (W + 2) into equation 1 for L \n" ); document.write( " \n" ); document.write( "Multiply the W through on the right hand side \n" ); document.write( " \n" ); document.write( "Subtract 34 from both sides \n" ); document.write( " \n" ); document.write( "Now you can use the quadratic equation to solve for W \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The quadratic equation tells us that W = 4.916 & -6.916 \n" ); document.write( "Since we can not have a negative distance we will only use W = 4.916 \n" ); document.write( "Now plug 4.916 into equation 2 for W \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The Length of the lawn is 6.196 yards and the Width is 4.916 yards \n" ); document.write( " \n" ); document.write( " |