document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903031>Question 903031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> we currently have 200 gallons of a 70% acidic solution that must be mixed with a solution of 13%acid to create a mixture of 29% acid. How much of the 13% acid do we need to create of solution 29% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547686 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.13*x+0.7*200=0.29(200+x)<BR>\n" );
document.write( "0.13*x+140=58+0.29x<BR>\n" );
document.write( "0.13x-0.29x=58-140<BR>\n" );
document.write( "-0.16x=-82<BR>\n" );
document.write( "x=512.5 gallons of 13% is added to 200 gallons of 70% to get  712.5 oz  at 29%<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.13*512.5+0.7*200=0.29(200+512.5)<BR>\n" );
document.write( "66.625+140=0.29(712.5)<BR>\n" );
document.write( "206.625=206.625<BR>\n" );
document.write( "ok\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );