document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903041>Question 903041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> m&#8736;K = (6x + 12)°. Find the measure of complement of &#8736;K. \r<BR>\n" );
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document.write( "(102 + 6x)°<BR>\n" );
document.write( "	(112 + 6x)°<BR>\n" );
document.write( "	(78 &#8722; 6x)°<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "	(67 &#8722; 6x)°\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547680 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 90° - (6x+12)°= (78-6x)° </SPAN>\n" );
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