document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=903014>Question 903014</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave towns 800 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hour less than the other's. If they meet in 5hours, what is the rate of the slower car? ( no rounding) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547654 by </B><A HREF=/tutors/aboutme.mpl?userid=tmwilliamlin168><B>tmwilliamlin168(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tmwilliamlin168><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547654\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=first car speed<BR>\n" );
document.write( "y=second car speed<BR>\n" );
document.write( "(x+y)*5=800<BR>\n" );
document.write( "60+5y=800<BR>\n" );
document.write( "5y=740<BR>\n" );
document.write( "y=148<BR>\n" );
document.write( "first car is slower, so the answer is 12km/hour<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );