document.write( "Question 902994: what is the solution for 14r to the 3rd power over r to the -8th power \n" ); document.write( "
Algebra.Com's Answer #547629 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
14r to the 3rd power over r to the -8th power
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document.write( "\"14r%5E3%2Fr%5E%28-8%29\"\r\n" );
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document.write( "Rule for a factor of a numerator of a denominator with\r\n" );
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document.write( "1.  If the factor with the negative exponent is in the NUMERATOR,\r\n" );
document.write( "    move it to the DENOMINATOR, changing the sign of the exponent \r\n" );
document.write( "    to positive.\r\n" );
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document.write( "and vice-verse:\r\n" );
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document.write( "2.  If the factor with the negative exponent is in the DENOMINATOR,\r\n" );
document.write( "    move it to the NUMERATOR, changing the sign of the exponent \r\n" );
document.write( "    to positive.\r\n" );
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document.write( "    \"14r%5E3r%5E8\"\r\n" );
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document.write( "Since there was no other factor in the denominator (other than 1 understood),\r\n" );
document.write( "we did not need to show a denominator of 1. \r\n" );
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document.write( "Now we add the exponents and get\r\n" );
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document.write( "    \"14r%5E11\"   <-- final answer\r\n" );
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document.write( "[However in other problems where the only factor is a negative exponent\r\n" );
document.write( "(other than 1) we must show the understood 1 factor in the numerator.]\r\n" );
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document.write( "Suppose your problem was:\r\n" );
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document.write( "\"x%5E%28-3%29%2Fx%5E2\"\r\n" );
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document.write( "We would then bring the \"x%5E%28-3%29\" to the denominator. But the next step \r\n" );
document.write( "would be\r\n" );
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document.write( "\"1%2F%28x%5E3x%5E2%29\" not \"cross%28x%5E3x%5E2%29\"\r\n" );
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document.write( "We would have to put the understood 1 factor in the numerator.\r\n" );
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document.write( "And then add the exponents in the denominator:\r\n" );
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document.write( "\"1%2Fx%5E5\"\r\n" );
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document.write( "Edwin
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