document.write( "Question 902938: Solve for r in terms of A. A=50(1+r/12)^12 \n" ); document.write( "
Algebra.Com's Answer #547605 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Comfort with logarithms needed.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A=50%281%2Br%2F12%29%5E12\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28A%29%29=log%28%2850%29%29%2Blog%28%28%281%2Br%2F12%29%5E12%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28A%29%29=log%28%2850%29%29%2B12%2Alog%28%281%2Br%2F12%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"12%2Alog%28%281%2Br%2F12%29%29=log%28%28A%2F50%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%281%2Br%2F12%29%29=%281%2F12%29log%28%28A%2F50%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Decide what base, b, you want.
\n" ); document.write( "(This is not rendering neatly, so it might fail to appear meaningful/readable):\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"b%5E%28%281%2F12%29log%28%28A%2F50%29%29%29=r%2F12%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"r%2F12=-1%2Bb%5E%28%281%2F12%29log%28%28A%2F50%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28r=-12%2B12%2Ab%5E%28%281%2F12%29log%28%28A%2F50%29%29%29%29\"
\n" ); document.write( "
\n" );