document.write( "Question 902895: how many pounds of almonds selling for $3 per pound should be mixed with 7 pounds of peanuts selling for $1.20 per pound to obtain a mixture worth $1.74 per pound \n" ); document.write( "

Algebra.Com's Answer #547586 by Edwin McCravy(20064) $\"\"$ $\"About$

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how many pounds of almonds selling for $3 per pound should be mixed with 7
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           \r\n" );
document.write( "         | number | price |           |\r\n" );
document.write( "         |   of   |  per  |   Total   |\r\n" );
document.write( "         | pounds | pound |   Value   |  \r\n" );
document.write( "---------|--------|-------|---------=-|\r\n" );
document.write( "almonds  |    x   | $3.00 |  $3.00x   |\r\n" );
document.write( "---------|--------|-------|-----------|\r\n" );
document.write( "peanuts  |    7   | $1.20 | $1.20(7)  |\r\n" );
document.write( "---------|--------|-------|-----------|\r\n" );
document.write( "mixture  |   x+7  | $1.74 |$1.74(x+7) |\r\n" );
document.write( "--------------------------------------|\r\n" );
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document.write( "The equation comes from:\r\n" );
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document.write( "     \r\n" );
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document.write( "   $3.00x + $1.20(7) = $1.74(x+7)\r\n" );
document.write( "       300x + 120(7) = 174(x+7)\r\n" );
document.write( "          300x + 840 = 174x + 1218\r\n" );
document.write( "                126x = 378\r\n" );
document.write( "                   x = 3\r\n" );
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document.write( "Answer:  3 pounds.\r\n" );
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document.write( "Edwin

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