document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902771>Question 902771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two opposite sides of a square are increased by 12 meters and the other sides are decreased by 6 meters, the area of the rectangle that is formed is 63 square meters. Find the area of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547522 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If two opposite sides of a square are increased by 12 meters and the other sides are decreased by 6 meters, the area of the rectangle that is formed is 63 square meters. Find the area of the original square.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(s+12)(s-6) = 63<BR>\n" );
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document.write( "s^2 + 6s - 72 = 63<BR>\n" );
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document.write( "s^2 + 6x - 135 = 0<BR>\n" );
document.write( "Factor::<BR>\n" );
document.write( "(s-9)(s+15) = 0<BR>\n" );
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document.write( "Positive solution::<BR>\n" );
document.write( "s = 9 meters<BR>\n" );
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document.write( "Original area:: s^2 = 81 sq meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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