document.write( "Question 902758: how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to obtain 15 liters of a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #547515 by ewatrrr(24785)\"\" \"About 
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.50x + .10(15L-x) = .30(15L)
\n" ); document.write( "x = .20(15L)/.40 = 7.5L, amount of 50%. Amount at 10% = \"15-x\"
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