document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902735>Question 902735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 6 times as long as it is wide. The area is 150 square feet. What is the perimeter of the rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547490 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 6 times as long as it is wide. The area is 150 square feet. What is the perimeter of the rectangle?<BR>\n" );
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document.write( "Width:: w<BR>\n" );
document.write( "Length = 6w<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "w*6w = 150<BR>\n" );
document.write( "6w^2 = 150<BR>\n" );
document.write( "w^2 = 25<BR>\n" );
document.write( "width = 5<BR>\n" );
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document.write( "length = 30<BR>\n" );
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document.write( "Perimeter = 2(length + width) = 2(35) = 70 ft.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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