document.write( "Question 902691: Suppose you invest $3,600 in stocks and bonds paying 7% and 3%, respectively. The interest from both investments after one year is $156. For the following problems, use x for the amount invested in stocks and y for the amount invested in bonds.
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document.write( "a) Write a mathematical expression for the total amount of money invested.
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document.write( "b) Write a mathematical expression for the total interest earned.
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document.write( "c) How much money was invested in bonds?
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Algebra.Com's Answer #547456 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! We know the total amount of money invested. $3600 \n" ); document.write( "A) x+y=3600, \n" ); document.write( "We know that the total interest for the year for the two accounts is $156 \n" ); document.write( "B)0.07*x+0.03*y=156 \n" ); document.write( "x=3600-y \n" ); document.write( "We substitute for x \n" ); document.write( "0.07*(3600-y)+0.03*y=156 \n" ); document.write( "We multiply out \n" ); document.write( "252-0.07y+0.03*y=156 \n" ); document.write( "We combine like terms. \n" ); document.write( "-0.04*y=-96 \n" ); document.write( "Isolate y \n" ); document.write( "C) y=2400 at 3% bonds \n" ); document.write( "x=3600-y \n" ); document.write( "Calculate x \n" ); document.write( "x=1200 at 7% stocks \n" ); document.write( "We check \n" ); document.write( "0.07*1200+0.03*2400=156 \n" ); document.write( "84+72=156 \n" ); document.write( "156=156 \n" ); document.write( "Since this statement is TRUE and neither amount is negative then it is ok \n" ); document.write( " \n" ); document.write( " |